# How do you find the vertex and the intercepts for #f(x) =x^2 + 3#?

##### 1 Answer

Jun 20, 2018

#### Explanation:

#"for a quadratic in the form "y=x^2+c#

#"the vertex has coordinates "=(0,c)#

#"here "c=3#

#color(magenta)"vertex "=(0,3)#

#"to find the x-intercepts let y = 0"#

#x^2+3=0rArrx^2=-3#

#"this has no real solutions, hence no x-intercepts"#

graph{x^2+3 [-10, 10, -5, 5]}